How much horsepower does a 1999 Dodge Dakota RT have?
Approximately 245 horsepower.
The 1999 Dodge Dakota R/T uses a 5.9-liter Magnum V8 to deliver this output, a figure that stood out for a compact pickup in the late 1990s. This article breaks down the engine, the horsepower figure, and what it meant for performance at the time.
Powertrain overview
The core figures for the Dakota R/T’s performance come from its 5.9-liter Magnum V8, a 360 cubic inch engine known for its stout torque and relatively strong high-end power for a pickup of its size. The following specifications summarize the key numbers owners and enthusiasts cited at the time.
- Engine: 5.9 L Magnum V8 (360 cubic inches)
- Horsepower: approximately 245 hp
- Torque: approximately 345 lb-ft
These figures helped the Dakota R/T stand out among mid-size pickups, offering a performance-oriented option in a segment that typically prioritized payload and practicality over outright speed.
Context and performance implications
With roughly 245 horsepower and about 345 pound-feet of torque, the Dakota R/T aimed to blend musclecar-like thrust with truck practicality. That power level allowed for brisk acceleration relative to non-R/T pickups of the era, and the V8 soundtrack complemented the vehicle’s sporty intent.
In the market of late-1990s pickups, the Dakota R/T’s engine and output positioned it as a dedicated performance-oriented option rather than a purely work-focused truck, attracting buyers who wanted both towing capability and a more engaging driving experience.
Summary
In summary, the 1999 Dodge Dakota R/T produced about 245 horsepower from its 5.9-liter Magnum V8, paired with substantial torque to deliver spirited acceleration for a compact pickup in its era. For enthusiasts, this combination helped define the R/T as a performance-oriented variant within the Dakota lineup.
How much horsepower does a 1999 Dodge Dakota Sport V8 have?
The text vehicle, a short-bed crew cab came with DaimlerChrysler's tried-but-true 5.2 liter V8. Known in another lifetime as the 318, this mill churns out a respectable 230 horsepower and 300 pound-feet of torque. Top of the heap is the 5.9-liter 250 horsepower V-8.
How much horsepower does a 1999 Dodge Dakota RT 5.9 have?
The 1999 Dodge Dakota R/T with the 5.9L V8 engine had 250 horsepower at 4,400 rpm and 345 pound-feet of torque at 3,200 rpm. This engine was exclusively available in the R/T model and was paired with a four-speed automatic transmission.
You can watch this video for a review of the Dodge Dakota R/T's engine and performance: 1mDriven CompanionYouTube · May 28, 2020
- Horsepower: 250 hp @ 4,400 rpm
- Torque: 345 lb-ft @ 3,200 rpm
- Engine: 5.9L Magnum V8
- Transmission: 4-speed automatic
How much horsepower does a 5.9 RT Dodge Dakota have?
The Dodge Dakota R/T with the 5.9L V8 engine produces 250 horsepower at 4,400 RPM and 345 lb-ft of torque at 3,200 RPM. This engine was available in 1998–2003 models and was also used in other high-performance Dodge vehicles.
You can watch this video to learn more about the Dodge Dakota R/T's engine: 58sTFLclassicsYouTube · Mar 4, 2024
- Horsepower: 250 hp at 4,400 rpm
- Torque: 345 lb-ft at 3,200 rpm
- Engine: 5.9L (360 cubic inch) V8 Magnum
- Transmission: 4-speed automatic (46RE)
- Drivetrain: Available in 2WD only
How much is a 1999 Dodge Dakota RT worth?
A 1999 Dodge Dakota Club Cab R/T has depreciated $310 or 7% in the last 3 years and has a current resale value of $3,729 and trade-in value of $2,002.
